How many 3-digit numbers have the property that the units digit is at least twice the tens digit?
I'm not very good at this but heres what I know: think about the options you have for each digit. The hundreds digit doesn't matter so you have 1-9 which is 10 options, then for the tens digit you can do casework for each number. For instance if it's 1, then the units digit is anything from 2-9. e.t.c
This is just one way of doing it:
Beginning with 1 as the hunderds digit, you have the following list:
102 103 104 105 106 107 108 109 112 113 114 115 116 117 118 119 124 125 126 127 128 129 136 137 138 139 148 149 =28 integers.
This same pattern repeats with:2, 3, 4, 5, 6, 7, 8, 9
So: 9 x 28 = 252 integers.