Let$f(x)=12x9+x$.Find$f(3)+f(−3)$.
Let$g(x)=4x2+x+7$.Find$g(−2)$.
Let$A(t)=3−2t2+4t$.Find$A(2)−A(1)$.
Let f(x)=2−3x5−2x For what value of f(a) is 3?
A) 0, because they cancel each other out. (the exponent is odd so the value will be negative, therefore they add to 0)
B) just solve, 4*4+(-2)+7 = 16-2+7 = 21
C) A(2) - A(1) = 15 - 5 = 10
D) set the expression equal to 3 (2-3x)/(5-2x) = 3 x = 13/3 Hope this helps!
