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Evaluate g(x)=x^2 for f(2+h)
 Jan 10, 2014

Best Answer 

 #1
avatar+5478 
+3
Evaluate g(x)=x^2 for f(2+h)

So basically that means you plug in (2+h) for every x in the equation.
So that would be:
g(x)=(2+h)^2
=(2+h) * (2+h)
Then, multiply it out.
 Jan 11, 2014
 #1
avatar+5478 
+3
Best AnswerEvaluate g(x)=x^2 for f(2+h)

So basically that means you plug in (2+h) for every x in the equation.
So that would be:
g(x)=(2+h)^2
=(2+h) * (2+h)
Then, multiply it out.
kitty<3 Jan 11, 2014
 #2
avatar+2 
0
How would I multiply it?
 Jan 11, 2014
 #3
avatar+118673 
0
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Thanks Kitty, you gave a really good answer.
applebee303:

How would I multiply it?


-------------------------------------------------------------
First, what is the area of a rectangle if the sides are 5m and 7m ?
Hopefully you know that the area is 5 x 7 = 35m 2
I am going to use this to show you how to expand double brackets.
--------------------------------------------------------------
I am not going to do yours I am going to do
(3+x)(x+3)
I have drawn a square where the sides are 3+x units long. And i have split it up as you can see into 4 bits - 2 at the top and 2 at the bottom

Just look at the top 2 sections (both put together)
It is a rectangle with 3 on the side and x+3 on the top. The area would be 3 times (x+3) that is 3(x+3)

Now we will look at the bottom bits
Again it is a recangle. x is on othe side and x+3 is the length of the top. The area would be x(x+3)

so now we have

(3+x)(x+3) = 3(x+3) +x(x+3)
Now you can expand the 2 brackets separately and then simplify by collecting the like terms.
If you don't know how to expand the 2 brackets you might be able to use the diagram to help you.

Of course you are not ging to draw the diagram every time i would think of it like this
I'd say, I have (3+x) lots of (x+3) so that is 3 lots of (x+3) + x lots of (x+3) = 3(x+3) +x(x+3)

Now you can do your one. Write and tell us what answer you get, it would be good if you include you working.
130108 (x+3) square.JPG
 Jan 11, 2014

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