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Let

f(x) = -x + 3 if x <= 0

f(x) = -2x - 5 if x > 0

 

How many solutions does the equation f(f(x)) = 4 have?

 May 31, 2021
 #1
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If your amount (4) is greater than 0, then you would use the equation -2x - 5.

 

So, for an official way to show your work: 
 

f(4) = -2x - 5

 

f(4) = -2(4) - 5

 

f(4) = -8 - 5

 

f(4) = -13 

4 doesn't equal -13, neither is -13 greater than 0, therefore this equation is inaccurate.

 

I believe that your answer has no solution due to it being a false equation. Therefore, the amount of solutions that your equation has is none. Feel free to correct me if I'm wrong though, since it has been a while since I have reviewed this..!

 Jun 1, 2021
edited by Alterr1  Jun 1, 2021

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