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Thanks!

Guest Feb 21, 2018
edited by Guest  Feb 22, 2018

Best Answer 

 #1
avatar+12266 
+2

a)  Max will be at the VERTEX of the parabola. the max value can be quickly found by t= -b/2a

      -96/-32 = t = 3

      sub 3 into the equation to find h-max     = 644

b. found in answer a to be t=3 sec

c 0 = -16t^2+96t+500     use quadratic fomual to find t=9.34 sec to the ground

d. 300 = 16t^2+96t+500                                               t=7.63

Here is a graph:

ElectricPavlov  Feb 21, 2018
edited by ElectricPavlov  Feb 21, 2018
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1+0 Answers

 #1
avatar+12266 
+2
Best Answer

a)  Max will be at the VERTEX of the parabola. the max value can be quickly found by t= -b/2a

      -96/-32 = t = 3

      sub 3 into the equation to find h-max     = 644

b. found in answer a to be t=3 sec

c 0 = -16t^2+96t+500     use quadratic fomual to find t=9.34 sec to the ground

d. 300 = 16t^2+96t+500                                               t=7.63

Here is a graph:

ElectricPavlov  Feb 21, 2018
edited by ElectricPavlov  Feb 21, 2018

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