#1**+2 **

a) Max will be at the VERTEX of the parabola. the max value can be quickly found by t= -b/2a

-96/-32 = t = 3

sub 3 into the equation to find h-max = 644

b. found in answer a to be t=3 sec

c 0 = -16t^2+96t+500 use quadratic fomual to find t=9.34 sec to the ground

d. 300 = 16t^2+96t+500 t=7.63

Here is a graph:

ElectricPavlov
Feb 21, 2018

#1**+2 **

Best Answer

a) Max will be at the VERTEX of the parabola. the max value can be quickly found by t= -b/2a

-96/-32 = t = 3

sub 3 into the equation to find h-max = 644

b. found in answer a to be t=3 sec

c 0 = -16t^2+96t+500 use quadratic fomual to find t=9.34 sec to the ground

d. 300 = 16t^2+96t+500 t=7.63

Here is a graph:

ElectricPavlov
Feb 21, 2018