+36916 a) Max will be at the VERTEX of the parabola. the max value can be quickly found by t= -b/2a
-96/-32 = t = 3
sub 3 into the equation to find h-max = 644
b. found in answer a to be t=3 sec
c 0 = -16t^2+96t+500 use quadratic fomual to find t=9.34 sec to the ground
d. 300 = 16t^2+96t+500 t=7.63
Here is a graph:
+36916 a) Max will be at the VERTEX of the parabola. the max value can be quickly found by t= -b/2a
-96/-32 = t = 3
sub 3 into the equation to find h-max = 644
b. found in answer a to be t=3 sec
c 0 = -16t^2+96t+500 use quadratic fomual to find t=9.34 sec to the ground
d. 300 = 16t^2+96t+500 t=7.63
Here is a graph:
