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The function f is defined by f(n) = f(n − 1) + f(n − 2). It is also true that f(1) = 3 and f(2) = 10. What is the value of f(6)

 Jun 4, 2022
 #1
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The function f is defined by f(n) = f(n - 1) + f(n - 2).
It is also true that f(1) = 3 and f(2) = 10.
What is the value of f(6)

 

\(\begin{array}{|rcll|} \hline \text{Let $f_n = f_{n-1}+ f_{n-2}$}\\ \hline f_1 &=& 3 \\ f_2&=& 10 \\ f_3&=& f_2+f_1 \\ &=& 10+3 \\ f_3 &=& 13 \\\\ f_4&=& f_3+f_2 \\ &=& 13+10 \\ f_4 &=& 23 \\\\ f_5&=& f_4+f_3 \\ &=& 23+13 \\ f_5 &=& 36 \\\\ f_6&=& f_5+f_4 \\ &=& 36+23 \\ \mathbf{f_6} &=& \mathbf{59} \\ \hline \end{array}\)

 

laugh

 Jun 4, 2022

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