Let $a\star b = \dfrac{\sqrt{a+b}}{\sqrt{a-b}}$. If $ x \star 24 = 7$, find $x$.
x must be 25 since sqrt(25+24) = sqrt(49) = 7, and sqrt(25-24) = sqrt(1) =1.
I am not familiar with this notation.
This is just defining the operator *.
You replace a by x, b by 24 and the result by 7 so:
Thanks Alan
note that 7-24-25 is a pythagorean triple
