+0  
 
0
81
2
avatar

If $f(x) = x^3 - 6x^2 + 3x - 4$, $g(x) = x^3 + 5x^2 + 9x - 2$, then find the constant term of $f(g(x))$.

 Mar 21, 2020
 #1
avatar+485 
+1

Hey guest!

Since we know that \(g(x) = x^3+5x^2+9x-2\), we already have part of the desired expression of f(g(x)).

The question then becomes reduced to: 

 

\(f(x^3+5x^2+9x-2)\)

since \(f(x) = x^3-6x^2+3x-4\), this may seem really complicated at first glance. However, remember what they ask us for; the constant term. That means we can ignore everything except for the constant term of the expression \(x^3+5x^2+9x-2\), which is -2.

Plugging -2 into the function \(f(x)\), we get:

\(f(-2) = (-2)^3-6(-2)^2+3(-2)-4 = -8-24-6-4 =-42\)

Thus, the constant term of the function f(g(x)) is -42

 Mar 21, 2020
 #2
avatar+2277 
+1

I agree! I think there might be an easier way though....

CalTheGreat  Mar 21, 2020

12 Online Users

avatar
avatar