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g^-1(x)=1 solve the equation

 Sep 7, 2014

Best Answer 

 #2
avatar+129839 
+10

A constant function doesn't have an inverse. To see why, note that if we have a function such as y = a, then it isn't one-to-one, because an infinite number of x values produce the same y value (namely, "a"). And  x = a can never have an inverse, because this is a vertical line - which doesn't meet the criteria of a "function." (It fails the vertical line test at x = a.)

That's my take on this one........

 

 Sep 7, 2014
 #1
avatar+118653 
0

Let me see

 

the inverse of x=1 would be y=1

The inverse of y=1 is x=1

 

So if the inverse of g(x) is 1 then I suppose g(x) can be anything in the domain of x=1

Umm

 

$$g(x)=k\qquad where\; k\in R \qquad and\;x=1$$

 

I definitely invite others to comment on this one.     

 Sep 7, 2014
 #2
avatar+129839 
+10
Best Answer

A constant function doesn't have an inverse. To see why, note that if we have a function such as y = a, then it isn't one-to-one, because an infinite number of x values produce the same y value (namely, "a"). And  x = a can never have an inverse, because this is a vertical line - which doesn't meet the criteria of a "function." (It fails the vertical line test at x = a.)

That's my take on this one........

 

CPhill Sep 7, 2014
 #3
avatar+118653 
0

Yes the inverse has to be a function.  Thanks Chris, I didn't think of that.   

 Sep 8, 2014

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