Let f(x) = 3x^2-3 and g(f(x)) = x^2 + x +1. Find the sum of all possible values of g(25).
Let's find what values of x make f(x) = 25
f(x) = 25
3x2 - 3 = 25
3x2 = 28
x2 = 28/3
x = ±√[ 28/3 ]
Now let's plug in both of these into g(f(x))
g( 25 ) = g(f( √[ 28/3 ] ) = ( √[ 28/3 ] )2 + √[ 28/3 ] + 1 = 31/3 + √[ 28/3 ]
g( 25 ) = g(f( -√[ 28/3 ] ) = ( -√[ 28/3 ] )2 - √[ 28/3 ] + 1 = 31/3 - √[ 28/3 ]
And adding these two together we get...
( 31/3 + √[ 28/3 ] ) + ( 31/3 - √[ 28/3 ] ) = 31/3 + 31/3 = 62/3
Agree with Hec ....guest answer is incorrect
25 = 3x^2-3
0 = 3x^2-28 quadratic formula shows x = +- 2 sqrt21 / 3
Sub into g(x) : (+2sqrt21/3)2 + 2 sqrt 21/3 +1 = ...........
and (-2sqrt21/3)2 - 2sqrt21/3 +1 = ............. you can do the math from here...should get same as hecticar