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Let \(P\) be the point (0,5),  let Q be the point (6,9), and let R be the point (12,0). Determine the area of right-angled \(\triangle PQR.\)

 Mar 14, 2018
 #1
avatar+98123 
+2

The right angle is PQR

 

Note that we can consider   PQ to be the  base   and QR to be the height

 

PQ  =  √ [  6^2  + ( 9 - 5)^2 ] = √ [6^2 + 4^2 ] = √ 52  = 2√13

QR  =√ [ (12 - 6)^2 + 9^2 ]  = √ [36 + 81 ]  = √117 =  3√13

 

So....the area  =   (1/2) base * height    =   (1/2) * (2 √13) * (3√13)  =  3*13  units^2  = 39 units^2

 

Thanks to AZSun for catching my error  !!!

 

 

cool cool cool

 Mar 14, 2018
edited by CPhill  Mar 14, 2018
 #2
avatar+3994 
+1

Thanks so much, CPhill! 

tertre  Mar 14, 2018
 #3
avatar+175 
+2

Slight mistake, CPhill?

azsun  Mar 14, 2018

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