Given a square with area A . A circle lies inside the square, such that the circle touches all sides of the square. Another square with area B lies inside the circle, such that all its vertices lie on the circle. Find the value of A/B.

Guest Dec 4, 2020

#1**+2 **

I found this, it may give you some help, but I need to solve it myself since I don't understand A WORD OF THAT since it is a pile of jumbled math to me: https://brainly.in/question/22637664.

Nacirema Dec 4, 2020

#2**+3 **

Call the side of the large square, S...and its area = S^2

The circle will have a diameter of S

Square B will have a diagonal of S and a side = (1/sqrt (2))S

So the area of B = [ (1/sqrt (2)) S ]^2 = S^2/2

So

A / B = S^2 / [ S^2/2 ] = 2 { the large square has twice the area of the small square )

CPhill Dec 4, 2020