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Given a square with area A . A circle lies inside the square, such that the circle touches all sides of the square. Another square with area B lies inside the circle, such that all its vertices lie on the circle.  Find the value of  A/B.

 Dec 4, 2020
 #1
avatar+339 
+2

I found this, it may give you some help, but I need to solve it myself since I don't understand A WORD OF THAT since it is a pile of jumbled math to me: https://brainly.in/question/22637664.

 Dec 4, 2020
 #2
avatar+114592 
+3

Call the side of  the large square, S...and its area =   S^2

 

The circle will have a  diameter  of  S

 

Square B  will  have a diagonal of S   and a side =  (1/sqrt (2))S

So the  area of B =   [ (1/sqrt (2)) S ]^2  =   S^2/2

 

So

 

A / B  =   S^2 / [ S^2/2  ]  =    2       { the large square has twice the area of the  small square  )

 

 

cool cool cool

 Dec 4, 2020
 #3
avatar+339 
+2

I was working it out with diagrams, see below:

Nacirema  Dec 4, 2020

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