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What is the range of possible sizes for side x?

 

 Aug 31, 2020
 #1
avatar+1039 
+1

Using the triangle inequality theorem, we can form these inequalities:

 

8 + 8.8 > x

8 + x > 8.8

x + 8.8 > 8

 

We technically don't need the third one, because we already know that x is greater than -0.8. (because lengthes can't be negative)

 

8 + 8.8 > x

8 + x > 8.8

 

We now need to isolate the "x" in the second inequality:

 

x > 8.8 - 8 

x > 0.8

 

Here is what we now know about x:

 

x < 16.8

x > 0.8

 

Therefore, the range for x is: {x | 0.8 < x < 16.8 } 

 

EXTRA KNOWLEDGE:

 

This is not needed, but the range in interval notation form is (0.8, 16.8)

 

EDIT: Sorry, I used the wrong numbers!

 

:)

 Aug 31, 2020
edited by ilorty  Aug 31, 2020
 #2
avatar+10597 
+1

What is the range of possible sizes for side x?

 

Hello Guest!


\(x \in \{\mathbb{R}\ |0.8 < x < 16.8 \}\)

laugh  !

 Aug 31, 2020
edited by asinus  Aug 31, 2020

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