#1**+2 **

Recall the geometric sequence formula for the nth term: \(a_n = a_1(r)^{n-1}\)

\(a_1 = 9\)

r = 1/6

n = 10

\(a_{10} = 9({1 \over 6})^9\)\(= {9 \over 6 ^ 9}\)\(= {1 \over 2^2 \cdot 6^7}\)

If you need a decimal form I believe that the calculator on this website should be able to provide you with that.

WhyamIdoingthis May 5, 2022

#1**+2 **

Best Answer

Recall the geometric sequence formula for the nth term: \(a_n = a_1(r)^{n-1}\)

\(a_1 = 9\)

r = 1/6

n = 10

\(a_{10} = 9({1 \over 6})^9\)\(= {9 \over 6 ^ 9}\)\(= {1 \over 2^2 \cdot 6^7}\)

If you need a decimal form I believe that the calculator on this website should be able to provide you with that.

WhyamIdoingthis May 5, 2022