geometric sequence

Recall the geometric sequence formula for the nth term: $a_n = a_1(r)^{n-1}$

$a_1 = 9$

r = 1/6

n = 10

$a_{10} = 9({1 \over 6})^9$$= {9 \over 6 ^ 9}$$= {1 \over 2^2 \cdot 6^7}$

If you need a decimal form I believe that the calculator on this website should be able to provide you with that.