+0

# Geometric sequence

+1
128
3
+27

A geometric sequece begins...

8,16,32,64...

Let x be 53rd term in this sequence. Compute \$\log_{2}(x)\$

Pls solve I am confused!!! Thank you!

May 11, 2022

#1
+1

log_2(x) = 58.

May 11, 2022
#2
+2448
+1

We can rewrite the geometric series as: \(2^3, 2^4, 2^5, 2^6, ...\), where the power is the nth term + 2.

This means that x = \(x = 2^ {53+2} = 2^{55}\)

Thus, we have \(\log_2(2^{55})\)

This is the same as: \(2^y = 2^{55}\), where y is our final answer. Can you take it from here?

May 11, 2022
#3
+27
+1

Yes thank you!

May 12, 2022