A geometric sequece begins...

8,16,32,64...

Let x be 53rd term in this sequence. Compute $\log_{2}(x)$

Pls solve I am confused!!! Thank you!

IcanhelpandIneedhelp May 11, 2022

#2**+1 **

We can rewrite the geometric series as: \(2^3, 2^4, 2^5, 2^6, ...\), where the power is the nth term + 2.

This means that x = \(x = 2^ {53+2} = 2^{55}\)

Thus, we have \(\log_2(2^{55})\).

This is the same as: \(2^y = 2^{55}\), where y is our final answer. Can you take it from here?

BuilderBoi May 11, 2022