A geometric sequece begins...
8,16,32,64...
Let x be 53rd term in this sequence. Compute \(\log_2(2x) - \log_2(x)\)
Note that \(log_2(2x)=log_2(2)+log_2(x)\) and \(log_2(2)=1\)
Alternatively, you can do it the long way by noting that the n'th term of the geometric sequence is given by \(2^{n+2}\).