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A geometric sequece begins...

8,16,32,64...

 

Let x be 53rd term in this sequence.  Compute \(\log_2(2x) - \log_2(x)\)

 May 21, 2022
 #1
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Note that \(log_2(2x)=log_2(2)+log_2(x)\) and \(log_2(2)=1\) 

 

Alternatively, you can do it the long way by noting that the n'th term of the geometric sequence is given by \(2^{n+2}\).

 May 22, 2022

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