If the second term of an arithmetic sequence is -7 and the fifth term is 16, then what is the fourteenth term?
Thank you!
2nd to 6th term is 4 d
4d = 16 - -7
d = 23/4
6th term to 14th term is eight mor d's
16 + (8)(23/4)
= 16 + 46 = ........
**** edit ***
2nd to 5th term is 3 d
3d = 16 - -7
d = 23/3
5th term to 14th term is nine mor d's
16 + (9)(23/3) = 85
Sorry for the error ....I originally used 16 as the SIXTH term instead of the FIFTH term
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-7 = F + D 16 = F + 4 D, solve for F, D
F =-44 / 3 - this is the first term
D = 23 / 3 - this is the common difference
14th term = - 44/3 + (23/3 * (14 - 1))
= - 44/3 + 99 2/3
= 85 - this is the 14th term.
