A rectangle is divided into four small rectangles as shown. The areas of three of the four small rectangles are labeled in the diagram. What is the area of the remaining small rectangle?

pls solve quickly! Thanks ;)

Guest Oct 3, 2017

edited by
Guest
Oct 3, 2017

edited by Guest Oct 3, 2017

edited by Guest Oct 3, 2017

edited by Guest Oct 3, 2017

edited by Guest Oct 3, 2017

edited by Guest Oct 3, 2017

edited by Guest Oct 3, 2017

#1**+2 **

ab = 4 → a = 4 / b

bd = 3

cd = 5 → c = 5 / d

area of remaining rectangle = ac = \(\frac4b\cdot\frac5d=\frac{20}{bd}=\frac{20}{3}\)

hectictar
Oct 3, 2017

#2**+2 **

Thanks, hectitctar!!!......there is a sligtly faster way of finding the missing area

Using hectictar's diagram [ along with a theorem from Euclid ]

area of ab * area of dc = area of bd * area of ac

4 * 5 = 3 * area of ac

20 = 3 * area of ac

Divide both sides by 3

20 / 3 = area of ac

CPhill
Oct 4, 2017