Circle F is intersected by HI and IJand m∠HIJ=101° What is the measure of HJ? Enter your answer in the box.
m< HIJ = (1/2) ( major arc HJ - minor arc HJ)
101° = (1/2) ( 281° - minor arc HJ ) multiply both sides by 2
202° = 281° - minor arc HJ rearrange as
minor arc HJ = [ 281 - 202] ° = 79°