Two long strips of paper are each 2 inches wide, and they overlap so that the angle between the strips is 15°. What is the number of square inches in the area of the parallelogram formed by the overlap?
+14995 Two long strips of paper are each 2 inches wide, and they overlap so that the angle between the strips is 15°. What is the number of square inches in the area of the parallelogram formed by the overlap?
Hello Guest!
\(A=\dfrac{2''}{sin\ 15°}\cdot2''\)
\(a=15.455\ square\ inches\)
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