+0  
 
+2
70
4
avatar+13 

Let AB = 5, BC = 12, and AC = 13. What is the circumradius of the triangle ABC?

 

What I tried so far:

I drew the triangle with the side lengths and realized that the point from A to the middle of BC forms a right angle, and splits 12 into half. 

 Nov 3, 2021
 #1
avatar
0

From the formula for circumradius, R = 85/12.

 Nov 3, 2021
 #2
avatar+13 
+1

Thank you!

Pigwidgeon  Nov 3, 2021
 #3
avatar+1608 
+2

Semi perimeter = 30/2

Area = sqrt[s(s-a)(s-b)(s-c)

Inradius = A/s

Circumradius (R) = (a*b*c) / (4*r*s)

R = 6.5

civonamzuk  Nov 3, 2021
 #4
avatar
0

Thank you, civonamzuk! laugh

Guest Nov 3, 2021

15 Online Users

avatar