Let AB = 5, BC = 12, and AC = 13. What is the circumradius of the triangle ABC?
What I tried so far:
I drew the triangle with the side lengths and realized that the point from A to the middle of BC forms a right angle, and splits 12 into half.
From the formula for circumradius, R = 85/12.
Semi perimeter = 30/2
Area = sqrt[s(s-a)(s-b)(s-c)
Inradius = A/s
Circumradius (R) = (a*b*c) / (4*r*s)
R = 6.5
Thank you, civonamzuk!