Let AB = 5, BC = 12, and AC = 13. What is the circumradius of the triangle ABC?

What I tried so far:

I drew the triangle with the side lengths and realized that the point from A to the middle of BC forms a right angle, and splits 12 into half.

Pigwidgeon Nov 3, 2021

#1

#3**+2 **

Semi perimeter = 30/2

Area = sqrt[s(s-a)(s-b)(s-c)

Inradius = A/s

Circumradius (R) = (a*b*c) / (4*r*s)

**R = 6.5**

civonamzuk
Nov 3, 2021