+4609 Two sides of an isosceles triangle are 10 inches and 20 inches. If the shortest side of a similar triangle is 50 inches, what is the perimeter of the larger triangle?
+9466 The sides of the first triangle are either 10, 10, 20 or 10, 20, 20 .
The sides cannot be 10, 10, 20 because for them to be sides of a triangle, this must be true:
10 + 10 > 20
20 > 20 This is not true, so the sides of the triangle cannot be 10, 10, 20 .
So the sides of the first triangle are 10, 20, 20 .
The shortest side of this triangle is 10 inches.
The shortest side of a similar triangle is 50 inches.
Each side of the similar triangle is 5 times the side of the first triangle.
The sides of the larger triangle are 10 * 5, 20 * 5, 20 * 5
The sides of the larger triangle are 50, 100, 100
the perimeter of the larger triangle = 50 + 100 + 100 = 250 (inches)
+9466 The sides of the first triangle are either 10, 10, 20 or 10, 20, 20 .
The sides cannot be 10, 10, 20 because for them to be sides of a triangle, this must be true:
10 + 10 > 20
20 > 20 This is not true, so the sides of the triangle cannot be 10, 10, 20 .
So the sides of the first triangle are 10, 20, 20 .
The shortest side of this triangle is 10 inches.
The shortest side of a similar triangle is 50 inches.
Each side of the similar triangle is 5 times the side of the first triangle.
The sides of the larger triangle are 10 * 5, 20 * 5, 20 * 5
The sides of the larger triangle are 50, 100, 100
the perimeter of the larger triangle = 50 + 100 + 100 = 250 (inches)
