We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.

+0

# geometry help!!!!!

+1
313
2

Two sides of an isosceles triangle are 10 inches and 20 inches. If the shortest side of a similar triangle is 50 inches, what is the perimeter of the larger triangle?

Mar 28, 2018

### Best Answer

#1
+3

The sides of the first triangle are either  10, 10, 20   or  10, 20, 20 .

The sides cannot be  10, 10, 20  because for them to be sides of a triangle, this must be true:

10 + 10  >  20

20 > 20   This is not true, so the sides of the triangle cannot be  10, 10, 20 .

So the sides of the first triangle are  10, 20, 20 .

The shortest side of this triangle is  10  inches.

The shortest side of a similar triangle is  50  inches.

Each side of the similar triangle is  5  times the side of the first triangle.

The sides of the larger triangle are  10 * 5, 20 * 5, 20 * 5

The sides of the larger triangle are  50, 100, 100

the perimeter of the larger triangle  =  50 + 100 + 100  =  250    (inches)

Mar 28, 2018

### 2+0 Answers

#1
+3
Best Answer

The sides of the first triangle are either  10, 10, 20   or  10, 20, 20 .

The sides cannot be  10, 10, 20  because for them to be sides of a triangle, this must be true:

10 + 10  >  20

20 > 20   This is not true, so the sides of the triangle cannot be  10, 10, 20 .

So the sides of the first triangle are  10, 20, 20 .

The shortest side of this triangle is  10  inches.

The shortest side of a similar triangle is  50  inches.

Each side of the similar triangle is  5  times the side of the first triangle.

The sides of the larger triangle are  10 * 5, 20 * 5, 20 * 5

The sides of the larger triangle are  50, 100, 100

the perimeter of the larger triangle  =  50 + 100 + 100  =  250    (inches)

hectictar Mar 28, 2018
#2
+3

Thanks so much, hectictar!!!!!!

tertre  Mar 28, 2018