Two sides of an isosceles triangle are 10 inches and 20 inches. If the shortest side of a similar triangle is 50 inches, what is the perimeter of the larger triangle?

tertre Mar 28, 2018

#1**+3 **

The sides of the first triangle are either 10, 10, 20 or 10, 20, 20 .

The sides cannot be 10, 10, 20 because for them to be sides of a triangle, this must be true:

10 + 10 > 20

20 > 20 This is not true, so the sides of the triangle cannot be 10, 10, 20 .

So the sides of the first triangle are 10, 20, 20 .

The shortest side of this triangle is 10 inches.

The shortest side of a similar triangle is 50 inches.

Each side of the similar triangle is 5 times the side of the first triangle.

The sides of the larger triangle are 10 * 5, 20 * 5, 20 * 5

The sides of the larger triangle are 50, 100, 100

the perimeter of the larger triangle = 50 + 100 + 100 = 250 (inches)

hectictar Mar 28, 2018

#1**+3 **

Best Answer

The sides of the first triangle are either 10, 10, 20 or 10, 20, 20 .

The sides cannot be 10, 10, 20 because for them to be sides of a triangle, this must be true:

10 + 10 > 20

20 > 20 This is not true, so the sides of the triangle cannot be 10, 10, 20 .

So the sides of the first triangle are 10, 20, 20 .

The shortest side of this triangle is 10 inches.

The shortest side of a similar triangle is 50 inches.

Each side of the similar triangle is 5 times the side of the first triangle.

The sides of the larger triangle are 10 * 5, 20 * 5, 20 * 5

The sides of the larger triangle are 50, 100, 100

the perimeter of the larger triangle = 50 + 100 + 100 = 250 (inches)

hectictar Mar 28, 2018