+0  
 
0
3
1
avatar+118 

Find angle ZAC.

 Jun 25, 2024

Best Answer 

 #1
avatar+10 
+1

In a right triangle the median has the same length as half the hypotenuse because of the circumcircle of the triangle. Therefore:

\(\triangle{ZCA}\) is isoceles and \(\angle{ZAC}=\angle{ZCA}=90-\angle{ABX}\)

\(\angle{ABX}=90-\angle{BAX}=90-(\frac{\angle{BAC}}{2}-\angle{XAY})=90-(45-22)=67\)

Thus \(\angle{ZAC}=\angle{ZCA}=90-67=\boxed{23}\)

 Jun 25, 2024
 #1
avatar+10 
+1
Best Answer

In a right triangle the median has the same length as half the hypotenuse because of the circumcircle of the triangle. Therefore:

\(\triangle{ZCA}\) is isoceles and \(\angle{ZAC}=\angle{ZCA}=90-\angle{ABX}\)

\(\angle{ABX}=90-\angle{BAX}=90-(\frac{\angle{BAC}}{2}-\angle{XAY})=90-(45-22)=67\)

Thus \(\angle{ZAC}=\angle{ZCA}=90-67=\boxed{23}\)

EnormousBighead Jun 25, 2024

2 Online Users

avatar