geometry help

I have a 3-4-5 triangle and they want me to find h, how do I find h?

In a right triangle:

\(\begin{array}{|rcll|} \hline h &=& \frac{ab}{c}\\ &=& \frac{3\cdot 4}{5} \\ &=& \frac{12}{5} \\ \mathbf{h} & \mathbf{=} & \mathbf{2.4} \\ \hline \end{array} \)

This is a right triangle  with legs of 3 and 4......the "5"  is the hypotenuse, "h"

Well, depends on if h is hypotenuse or height

Ah.......thanks, raindropsfurrever and heureka......I wasn't thinking in terms of "h" being the height

BTW........here's how heureka gets his formula......

Let a and  be legs......

Then the area  is  (1/2) ab

Now.......draw an altitude, h, to the hypotenuse, C

Then the area  is   (1/2)ch

Equating areas,  we have

(1/2)AB  = (1/2) ch    

ab  = ch      divide by  c

ab/c  = h