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# geometry help

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I have a 3-4-5 triangle and they want me to find h, how do I find h?

Guest Mar 2, 2017

#3
+19653
+5

I have a 3-4-5 triangle and they want me to find h, how do I find h?

In a right triangle:

$$\begin{array}{|rcll|} \hline h &=& \frac{ab}{c}\\ &=& \frac{3\cdot 4}{5} \\ &=& \frac{12}{5} \\ \mathbf{h} & \mathbf{=} & \mathbf{2.4} \\ \hline \end{array}$$

heureka  Mar 2, 2017
#1
+87333
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This is a right triangle  with legs of 3 and 4......the "5"  is the hypotenuse, "h"

CPhill  Mar 2, 2017
#2
+54
+5

Well, depends on if h is hypotenuse or height

raindropsfurrever  Mar 2, 2017
#3
+19653
+5

I have a 3-4-5 triangle and they want me to find h, how do I find h?

In a right triangle:

$$\begin{array}{|rcll|} \hline h &=& \frac{ab}{c}\\ &=& \frac{3\cdot 4}{5} \\ &=& \frac{12}{5} \\ \mathbf{h} & \mathbf{=} & \mathbf{2.4} \\ \hline \end{array}$$

heureka  Mar 2, 2017
#4
+87333
0

Ah.......thanks, raindropsfurrever and heureka......I wasn't thinking in terms of "h" being the height

BTW........here's how heureka gets his formula......

Let a and  be legs......

Then the area  is  (1/2) ab

Now.......draw an altitude, h, to the hypotenuse, C

Then the area  is   (1/2)ch

Equating areas,  we have

(1/2)AB  = (1/2) ch

ab  = ch      divide by  c

ab/c  = h

CPhill  Mar 2, 2017