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I have a 3-4-5 triangle and they want me to find h, how do I find h?

Guest Mar 2, 2017

Best Answer 

 #3
avatar+19653 
+5

I have a 3-4-5 triangle and they want me to find h, how do I find h?

 

In a right triangle:

\(\begin{array}{|rcll|} \hline h &=& \frac{ab}{c}\\ &=& \frac{3\cdot 4}{5} \\ &=& \frac{12}{5} \\ \mathbf{h} & \mathbf{=} & \mathbf{2.4} \\ \hline \end{array} \)

 

laugh

heureka  Mar 2, 2017
 #1
avatar+87333 
0

This is a right triangle  with legs of 3 and 4......the "5"  is the hypotenuse, "h"

 

 

cool cool cool

CPhill  Mar 2, 2017
 #2
avatar+54 
+5

Well, depends on if h is hypotenuse or height

raindropsfurrever  Mar 2, 2017
 #3
avatar+19653 
+5
Best Answer

I have a 3-4-5 triangle and they want me to find h, how do I find h?

 

In a right triangle:

\(\begin{array}{|rcll|} \hline h &=& \frac{ab}{c}\\ &=& \frac{3\cdot 4}{5} \\ &=& \frac{12}{5} \\ \mathbf{h} & \mathbf{=} & \mathbf{2.4} \\ \hline \end{array} \)

 

laugh

heureka  Mar 2, 2017
 #4
avatar+87333 
0

Ah.......thanks, raindropsfurrever and heureka......I wasn't thinking in terms of "h" being the height

 

BTW........here's how heureka gets his formula......

 

Let a and  be legs......

 

Then the area  is  (1/2) ab

 

Now.......draw an altitude, h, to the hypotenuse, C

 

Then the area  is   (1/2)ch

 

Equating areas,  we have

 

(1/2)AB  = (1/2) ch    

 

ab  = ch      divide by  c

 

ab/c  = h

 

 

cool cool cool

CPhill  Mar 2, 2017

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