Let P_1 P_2 P_3 \dotsb P_{10} be a regular polygon inscribed in a circle with radius $1.$ Compute
P_1 P_2 + P_2 P_3 + P_3 P_4 + \dots + P_9 P_{10} + P_{10} P_1
In order to solve this problem, we have to note something very important!
P1P2P3⋯P10 forms a regular decagon!
This means that P1P2+P2P3+P3P4+⋯+P9P10+P10P1 is just the perimeter of that regular decagon
In order to find one side length of the decagon, we can use the equation
radius2(−1+√5)
Using information from the problem, we can easily find the perimeter.
10(1/2)(−1+√5)=5(−1+√5)≈6.18
So 6.18 is about our answer!
Thanks! :)