geometry help

Triangles ABC and ADE have areas \(2007\) and \(7002\) respectively, with
\(B=(0,0)\), \(C=(223,0)\), \(D=(680,380)\), and \(E=(689,389)\).
What is the sum of all possible x-coordinates of \(A\)?

(The answer is not -1238)

First solution for \(y_A\):

\(\begin{array}{rcl} \mathbf{\text{2[ABC]} } = \begin{array}{|rr|} x_A & y_A \\ 0 & 0 \\ 223 & 0 & \\ x_A & y_A \\ \end{array} &=& 2* 2007 \\\\ \begin{array}{|rr|} x_A & y_A \\ 0 & 0 \\ 223 & 0 & \\ x_A & y_A \\ \end{array} &=& 2* 2007 \\ \begin{array}{|rr|} x_A*0-0*y_A + 0*0-223*0+223*y_A-x_A*0 \end{array} &=& 2* 2007 \\ 223*y_A&=& 2* 2007 \quad | \quad : 223 \\ \mathbf{y_A} &=& \mathbf{18} \\ \end{array} \)

First solution for \(x_A\):

\(\begin{array}{rcl} \mathbf{\text{2[ADE]} } = \begin{array}{|rr|} x_A & 18 \\ 680 & 380 \\ 689 & 389 & \\ x_A & 18 \\ \end{array} &=& 2* 7002 \\\\ \begin{array}{|rr|} x_A & 18 \\ 680 & 380 \\ 689 & 389 & \\ x_A & 18 \\ \end{array} &=& 2* 7002 \\ \begin{array}{|rr|} 380x_A-680*18+680*389-689*380+689*18-389x_A \end{array} &=& 2* 2007 \\ -9x_A+680*371-689*362 &=& 2* 7002 \\ -9x_A+2862 &=& 2* 7002 \quad | \quad : (-9) \\ x_A - 318 &=& -1556\\ \mathbf{x_A} &=& \mathbf{-1238} \\ \end{array}\)

Second solution for \(x_A\):

\(\begin{array}{rcl} \mathbf{\text{2[ADE]} } = \begin{array}{|rr|} x_A & 18 \\ 689 & 389 \\ 680 & 380 \\ x_A & 18 \\ \end{array} &=& 2* 7002 \\\\ \begin{array}{|rr|} x_A & 18 \\ 689 & 389 \\ 680 & 380 \\ x_A & 18 \\ \end{array} &=& 2* 7002 \\ \begin{array}{|rr|} 389x_A-689*18+689*380-680*389+680*18-380x_A \end{array} &=& 2* 2007 \\ 9x_A+689*362-689*371 &=& 2* 7002 \\ 9x_A-2862 &=& 2* 7002 \quad | \quad : 9 \\ x_A - 318 &=& 1556\\ \mathbf{x_A} &=& \mathbf{1874} \\ \end{array}\)

Second solution for \(y_A\):

\(\begin{array}{rcl} \mathbf{\text{2[ABC]} } = \begin{array}{|rr|} x_A & y_A \\ 223 & 0 & \\ 0 & 0 \\ x_A & y_A \\ \end{array} &=& 2* 2007 \\\\ \begin{array}{|rr|} x_A & y_A \\ 223 & 0 & \\ 0 & 0 \\ x_A & y_A \\ \end{array} &=& 2* 2007 \\ \begin{array}{|rr|} x_A*0-223*y_A +223*0 - 0*0 + 0*y_A -x_A*0 \end{array} &=& 2* 2007 \\ -223*y_A&=& 2* 2007 \quad | \quad : (-223) \\ \mathbf{y_A} &=& \mathbf{-18} \\ \end{array}\)

Third Solution for \(x_A\):

\( \begin{array}{rcl} \mathbf{\text{2[ADE]} } = \begin{array}{|rr|} x_A & -18 \\ 680 & 380 \\ 689 & 389 & \\ x_A & -18 \\ \end{array} &=& 2* 7002 \\\\ \begin{array}{|rr|} x_A & -18 \\ 680 & 380 \\ 689 & 389 & \\ x_A & -18 \\ \end{array} &=& 2* 7002 \\ \begin{array}{|rr|} 380x_A+680*18+680*389-689*380-689*18-389x_A \end{array} &=& 2* 2007 \\ -9x_A+680*407-689*398 &=& 2* 7002 \\ -9x_A+2538 &=& 2* 7002 \quad | \quad : (-9) \\ x_A - 282 &=& -1556\\ \mathbf{x_A} &=& \mathbf{-1274} \\ \end{array} \)

Fourth Solution for \(x_A\):

\(\begin{array}{rcl} \mathbf{\text{2[ADE]} } = \begin{array}{|rr|} x_A & -18 \\ 689 & 389 \\ 680 & 380 \\ x_A & -18 \\ \end{array} &=& 2* 7002 \\\\ \begin{array}{|rr|} x_A & -18 \\ 689 & 389 \\ 680 & 380 \\ x_A & -18 \\ \end{array} &=& 2* 7002 \\ \begin{array}{|rr|} 389x_A+689*18+689*380-680*389-680*18-380x_A \end{array} &=& 2* 2007 \\ 9x_A+689*398-680*407 &=& 2* 7002 \\ 9x_A-2538 &=& 2* 7002 \quad | \quad : 9 \\ x_A - 282 &=& 1556\\ \mathbf{x_A} &=& \mathbf{1838} \\ \end{array}\)

The sum of all possible x-coordinates of \(A\) is \(-1238+1874-1274+1838 = \mathbf{1200}\)

I think there are four possibilities for A; see https://web2.0calc.com/questions/triangles-abc-and-ade-have-areas-2007-and-7002-respectively#r3