+152 Hi, so this is the beginning of the problem (down there)
And so I did that, I made the scale drawing. But I need help with the following questions:
b. record your estimate from part (a) in the table where CP = 0
c. do the same with point p chosen successively between c and d so that CP = 100ft, 200ft, 1200ft.
d. in each case, use your protractor to measure angle 1 (the angle at which he approaches the river) and angle 2 (the angle at which he leaves the river)
if you want, I can post my scale drawing to make things easier. THANK YOU SO MUCH.
+33616 The following doesn't do all you want it to, but it does show how to calculate the shortest path, and what the angle is:
+128475 Using Calculus, we can show that the shortest distance occurs when :
tan (APC) = tan (BPD)
Let PC = x and let PD = 1200 - x
So.....tan (APC) = 600/x and tan (BPD) = 300/(1200 - x)
So we have :
600/x = 300 / (1200 - x) → 2/x = 1/(1200 - x) cross multiply
2(1200 - x) = x
2400 - 2x = x add 2x to both sides
2400 = 3x divide both sides by 3
800 = x = PC ...... So he should aim for point P, 800 ft from point C
