We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website.
Please click on "Accept cookies" if you agree to the setting of cookies. Cookies that do not require consent remain unaffected by this, see
cookie policy and privacy policy.
DECLINE COOKIES

A person is standing 40 ft away from a flagpole and can see the top of the pole at a 35 degree angle of elevation .The person's eye level is 4 ft from the ground.what is the height of the flagpole to the nearest foot?

Guest Jan 31, 2012

#1**0 **

flagpole.png

α = 35 deg

**tan( α ) = h/40ft**

h = tan( α ) * 40ft

[input]tan( 35 ) * 40ft[/input]

h ≈ 28ft

Flag pole height ≈ 4ft+28ft =**32ft**

Guest:A person is standing 40 ft away from a flagpole and can see the top of the pole at a 35 degree angle of elevation .The person's eye level is 4 ft from the ground.what is the height of the flagpole to the nearest foot?

flagpole.png

α = 35 deg

h = tan( α ) * 40ft

[input]tan( 35 ) * 40ft[/input]

h ≈ 28ft

Flag pole height ≈ 4ft+28ft =

admin Feb 1, 2012