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geometry problem

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The perimeter of a rectangular garden is 690 ft. The width is 30 less than twice the length. Find the dimensions of the garden.

Mar 2, 2021

#1
+487
+3

690/2 is the length of the width+length, which is 345. if w=2l-30 and w+l=345, then subtracting one equation from the other, we have

l=-2l+375

3l=375

length=\$\boxed{125}\$ft

now that we have the length, we can plug it in with one of the equations to solve for w:

w+125=345

width=\$\boxed{220}\$ft

Mar 2, 2021
edited by SparklingWater2  Mar 2, 2021
#2
+118069
+1

Just a slight error  by SparklingWater

W =  2L - 30

P  =  2 ( W + L)

690  = 2  ( 2L - 30  + L )

690  =  2 ( 3L - 30)

690   /  2  =   3L  -30

345  = 3L  - 30

345 + 30  =  3L

375  = 3L

L = 375 / 3  =  125

W  = 2 (125)  - 30  =  220

2 ( W + L)   = 2 ( 125 + 220) =  2 (345)  =   690

Mar 2, 2021
#3
+487
+3

whoops... didn't see it said "less"... thank you CPhill

SparklingWater2  Mar 2, 2021
#4
+118069
+1

No biggie   !!!!

CPhill  Mar 2, 2021