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The perimeter of a rectangular garden is 690 ft. The width is 30 less than twice the length. Find the dimensions of the garden.

 Mar 2, 2021
 #1
avatar+487 
+3

690/2 is the length of the width+length, which is 345. if w=2l-30 and w+l=345, then subtracting one equation from the other, we have

 

l=-2l+375

3l=375

length=$\boxed{125}$ft

 

now that we have the length, we can plug it in with one of the equations to solve for w:

 

w+125=345

width=$\boxed{220}$ft

 Mar 2, 2021
edited by SparklingWater2  Mar 2, 2021
 #2
avatar+118069 
+1

Just a slight error  by SparklingWater

 

W =  2L - 30

 

P  =  2 ( W + L)

 

690  = 2  ( 2L - 30  + L )

 

690  =  2 ( 3L - 30)

 

690   /  2  =   3L  -30

 

345  = 3L  - 30

 

345 + 30  =  3L

 

375  = 3L

 

L = 375 / 3  =  125

 

W  = 2 (125)  - 30  =  220

 

2 ( W + L)   = 2 ( 125 + 220) =  2 (345)  =   690

cool cool cool

 Mar 2, 2021
 #3
avatar+487 
+3

whoops... didn't see it said "less"... thank you CPhill

SparklingWater2  Mar 2, 2021
 #4
avatar+118069 
+1

No biggie   !!!!

 

 

cool cool cool

CPhill  Mar 2, 2021

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