+1452 A square is constructed using the hypotenuse line AC of right triangle ABC as a side, as shown below. Find the area of the square if AB = 5 and $BC = 9.
Thanks!
Edit: So sorry I forgot the image!
+223 area of triangle = 1/2 * base * height
area of traingle = 1/2 * 5 * 9
area of traingle = 1/2 * 45
area of triangle = 22.5
triangle * number of triangles that can fit in square will give you the area of the square
+129852 We need to find AC...it will be the hypotenuse of right triangle ABC
So we have
AC = √ [ AB^2 + BC^2 ] = √ [ 5^2 + 9^2 ] = √ [ 25 + 81 ] = √ 106
So....the area of the square is just the square of this = 106 units^2
