+0  
 
+2
97
4
avatar+1146 

A square is constructed using the hypotenuse line AC of right triangle ABC as a side, as shown below. Find the area of the square if AB = 5 and $BC = 9.

 

 

 

Thanks!

 

Edit: So sorry I forgot the image!

AnonymousConfusedGuy  Feb 13, 2018
edited by AnonymousConfusedGuy  Feb 13, 2018

Best Answer 

 #3
avatar+86944 
+2

We need to find AC...it will be the hypotenuse of right triangle ABC

 

So we have

 

AC  =  √ [ AB^2 + BC^2  ] =  √ [ 5^2 + 9^2  ] =  √ [ 25 + 81  ] = √ 106

 

So....the area of the square is just the square of this  = 106 units^2

 

 

cool cool cool

CPhill  Feb 13, 2018
 #1
avatar+544 
+1

it is not shown below?

 

 

winkwinkwink

lynx7  Feb 13, 2018
 #2
avatar+544 
+1

area of triangle = 1/2 * base * height

area of traingle = 1/2 * 5 * 9

area of traingle = 1/2 * 45

area of triangle = 22.5

triangle * number of triangles that can fit in square will give you the area of the square

 

 

winkwinkwink 

lynx7  Feb 13, 2018
 #3
avatar+86944 
+2
Best Answer

We need to find AC...it will be the hypotenuse of right triangle ABC

 

So we have

 

AC  =  √ [ AB^2 + BC^2  ] =  √ [ 5^2 + 9^2  ] =  √ [ 25 + 81  ] = √ 106

 

So....the area of the square is just the square of this  = 106 units^2

 

 

cool cool cool

CPhill  Feb 13, 2018
 #4
avatar+1146 
+2

Thanks so much you guys!

AnonymousConfusedGuy  Feb 13, 2018
edited by AnonymousConfusedGuy  Feb 13, 2018

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