A square is constructed using the hypotenuse line AC of right triangle ABC as a side, as shown below. Find the area of the square if AB = 5 and $BC = 9.

Thanks!

Edit: So sorry I forgot the image!

AnonymousConfusedGuy Feb 13, 2018

#2**+1 **

area of triangle = 1/2 * base * height

area of traingle = 1/2 * 5 * 9

area of traingle = 1/2 * 45

area of triangle = 22.5

triangle * number of triangles that can fit in square will give you the area of the square

lynx7 Feb 13, 2018

#3**+2 **

Best Answer

We need to find AC...it will be the hypotenuse of right triangle ABC

So we have

AC = √ [ AB^2 + BC^2 ] = √ [ 5^2 + 9^2 ] = √ [ 25 + 81 ] = √ 106

So....the area of the square is just the square of this = 106 units^2

CPhill Feb 13, 2018