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# Geometry problem

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A square is constructed using the hypotenuse line AC of right triangle ABC as a side, as shown below. Find the area of the square if AB = 5 and \$BC = 9.

Thanks!

Edit: So sorry I forgot the image!

Feb 13, 2018
edited by AnonymousConfusedGuy  Feb 13, 2018

#3
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We need to find AC...it will be the hypotenuse of right triangle ABC

So we have

AC  =  √ [ AB^2 + BC^2  ] =  √ [ 5^2 + 9^2  ] =  √ [ 25 + 81  ] = √ 106

So....the area of the square is just the square of this  = 106 units^2

Feb 13, 2018

#1
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it is not shown below?

Feb 13, 2018
#2
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area of triangle = 1/2 * base * height

area of traingle = 1/2 * 5 * 9

area of traingle = 1/2 * 45

area of triangle = 22.5

triangle * number of triangles that can fit in square will give you the area of the square

Feb 13, 2018
#3
+100516
+2

We need to find AC...it will be the hypotenuse of right triangle ABC

So we have

AC  =  √ [ AB^2 + BC^2  ] =  √ [ 5^2 + 9^2  ] =  √ [ 25 + 81  ] = √ 106

So....the area of the square is just the square of this  = 106 units^2

CPhill Feb 13, 2018
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+1433
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Thanks so much you guys!

Feb 13, 2018
edited by AnonymousConfusedGuy  Feb 13, 2018