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ABCD is a square with side length 2.
What is the length of DH?

 

 Sep 9, 2020
 #1
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I don't like incomplete questions. cheeky This is NOT solvable!!!

 

But, we can make it solvable by adding this:  BC = CF

 

∠AFC = arctan(AB / BF) = 26.56505118º                ∠AFC = ∠ABG = β

 

AG = sin( β ) * AB = 0.894427191

 

AH = cos( β ) * AG = 0.8

 

DH = AD - AH = 1.2 units  smiley

 Sep 10, 2020

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