ABCD is a square with side length 2. What is the length of DH?
I don't like incomplete questions. This is NOT solvable!!!
But, we can make it solvable by adding this: BC = CF
∠AFC = arctan(AB / BF) = 26.56505118º ∠AFC = ∠ABG = β
AG = sin( β ) * AB = 0.894427191
AH = cos( β ) * AG = 0.8
DH = AD - AH = 1.2 units