A quarter-circle (R) is inscribed in a square. A circle (r) is drawn. Find the ratio of r to R.
The diagonal of the square is \(\sqrt{2R^2}\)
You need to check my working for stupid errors.
ok jugoslav,
I will mark just one of your errors
DB = sqrt(2 * R) sqrt(2 * R2) wrong
\(DB=\sqrt{R^2+R^2}\\ DB=\sqrt{2R^2}\\ DB=\sqrt2 * \sqrt{R^2}\\ DB=\sqrt{2} *R\)
Your answer does not give a ratio at all. We already know that the ratio is r:R that is given in the question.
Yours does not simplify to that so it is not correct.
PLUS the whole point is to put R in terms of r
Note: it is really good that you are questioning my solution.
That shows everyone here that you are actively learning.
Your answer is r : R
1 : 3 - 2√2 ( 1 : -0.17157287525381 )
The correct answer is: 1 : 3 + 2√2 or 1 : 5.828427124746190666
Maybe so, I already said my answer needed to be checked for stupid errors.
Everyone can see that your second post answer #3, which was completely wrong, has been edited in the past half hour, (after I posted mine.)
Stop trying to be so dishonest.