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Each triangle in this figure is an isosceles right triangle. The length of \(BD\) is 2 units. What is the number of units in the perimeter of quadrilateral \(ABCD\)? Express your answer in simplest radical form.

 


 Aug 2, 2020
 #1
avatar+27660 
+1

BD = 2    Use pythag theorem to find sides ab  and ad   =   sqrt2

 

   then DC = 2

       and    CB =  sqrt 8                         soooooo     2   + 2 sqrt2  + sqrt8 =    2 + 4 sqrt2

 Aug 3, 2020
 #2
avatar+1035 
+4

Hello! Are you able to see the picture,or was it blocked by moderator? Thanks!

ilorty  Aug 3, 2020
 #3
avatar+111089 
+2

The pic is blocked for me and I cannot unblock it.  It is probably visible on the answer tab.

Alan has also been having this problem a lot lately.    angry

Melody  Aug 3, 2020
 #4
avatar+1035 
+3

Ive also been getting a lot of the same problems, and it's pretty frustrating. But, oh well, the rest of the site seems to be fine.....laugh

ilorty  Aug 3, 2020
 #5
avatar+25569 
+3

The address of the pic is: https://web2.0calc.com/img/upload/9de3171bf728a80bb304cee0/geometry-1.png

 

 

laugh

 Aug 3, 2020
edited by heureka  Aug 4, 2020
edited by heureka  Aug 4, 2020
edited by heureka  Aug 4, 2020
 #6
avatar+1035 
+6

Thanks heureka!

ilorty  Aug 3, 2020
 #7
avatar
+1

Each triangle in this figure is an isosceles right triangle. The length of BD is 2 units. What is the number of units in the perimeter of the quadrilateral ABCD? Express your answer in simplest radical form.

 

Perimeter  P = 2√2 + √8 + √4  wink

 Aug 5, 2020
edited by Guest  Aug 5, 2020

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