Each triangle in this figure is an isosceles right triangle. The length of \(BD\) is 2 units. What is the number of units in the perimeter of quadrilateral \(ABCD\)? Express your answer in simplest radical form.
BD = 2 Use pythag theorem to find sides ab and ad = sqrt2
then DC = 2
and CB = sqrt 8 soooooo 2 + 2 sqrt2 + sqrt8 = 2 + 4 sqrt2
Hello! Are you able to see the picture,or was it blocked by moderator? Thanks!
The pic is blocked for me and I cannot unblock it. It is probably visible on the answer tab.
Alan has also been having this problem a lot lately.
The address of the pic is: https://web2.0calc.com/img/upload/9de3171bf728a80bb304cee0/geometry-1.png