A gecko is in a room that is 12 feet long, 10 feet wide and 8 feet tall. The gecko is currently on a side wall (10 by 8), one foot from the ceiling and one foot from the back wall (12 by 8). The gecko spots a fly on the opposite side wall, one foot from the floor and one foot from the front wall. What is the length of the shortest path the gecko can take to reach the fly assuming that it does not jump and can only walk across the ceiling and the walls? Express your answer in simplest radical form.

Guest Feb 12, 2020

#1**+3 **

Drawing a picture can HELPPPPPPP

The Gecko is 6 feet above the fly (vertical), 8 feet horizontally forward from it, and 12 feet horizontally left from it.

We first use pythagorean theorem.

8^{2} + 12^{2} = 208

\(\sqrt{208}=4\sqrt{13}\)

Ok then we use the pythagorean theorem again.

6^{2} + \((4\sqrt{13}^2)\) = 244

\(\sqrt{244}=\boxed{2\sqrt{61}}\)

PLEASE CHECK THIS IS PROBABLY SUPER DUPER BUPER MOOPER LOOPER WRONG!!!!

CalculatorUser Feb 12, 2020

edited by
CalculatorUser
Feb 12, 2020

edited by CalculatorUser Feb 12, 2020

edited by CalculatorUser Feb 12, 2020

edited by CalculatorUser Feb 12, 2020

edited by CalculatorUser Feb 12, 2020

#2**+5 **

Push the two walls shown in CalculatorUser's picture outward until they lie flat on the ground. Then the "x-direction" distance between the two points is 7 + 12 + 1 or 20. The "y-direction" distance is 10 - 2 or 8. So the straight line between the points is given by Pythagoras as sqrt(20^{2} + 8^{2}) or 4sqrt(29)

Alan Feb 12, 2020