Geometry Question

$\angle BCD=\frac12(\overset{\frown}{AE}-\overset{\frown}{BD}) \\~\\ 36^{\circ}=\frac12(\overset{\frown}{AE}-26^{\circ}) \qquad\text{ Multiply both sides of the equation by 2.} \\~\\ 2\,*\,36^{\circ}=\overset{\frown}{AE}-26^{\circ}\qquad\text{Add 26 degrees to both sides of the equation.}\\~\\ 2\,*\,36^{\circ}+26^{\circ}=\overset{\frown}{AE} \\~\\ 98^{\circ}=\overset{\frown}{AE}$