Does anyone know the formulas involved? If you could walk me through this problem i would really appreciate that! Thank you.

Guest Mar 12, 2018

#1**+2 **

sin x = opposite / hypotenuse in a right triangle

remember sin 45 dgrees = sqrt2 / 2

so for the triangle on the LEFT sin 45 = sqrt(2) /2 = a/(7 sqrt(2) ) solve for a

(7 * sqrt2) * sqrt(2)/2 = a

14/2 = a = 7

ElectricPavlov
Mar 12, 2018

#1**+2 **

Best Answer

sin x = opposite / hypotenuse in a right triangle

remember sin 45 dgrees = sqrt2 / 2

so for the triangle on the LEFT sin 45 = sqrt(2) /2 = a/(7 sqrt(2) ) solve for a

(7 * sqrt2) * sqrt(2)/2 = a

14/2 = a = 7

ElectricPavlov
Mar 12, 2018