Does anyone know the formulas involved? If you could walk me through this problem i would really appreciate that! Thank you.
+37146 sin x = opposite / hypotenuse in a right triangle
remember sin 45 dgrees = sqrt2 / 2
so for the triangle on the LEFT sin 45 = sqrt(2) /2 = a/(7 sqrt(2) ) solve for a
(7 * sqrt2) * sqrt(2)/2 = a
14/2 = a = 7
+37146 sin x = opposite / hypotenuse in a right triangle
remember sin 45 dgrees = sqrt2 / 2
so for the triangle on the LEFT sin 45 = sqrt(2) /2 = a/(7 sqrt(2) ) solve for a
(7 * sqrt2) * sqrt(2)/2 = a
14/2 = a = 7
