+0

0
101
4
+92

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https://prnt.sc/hxrcqz part 2

https://prnt.sc/hxrdwa part 1

https://prnt.sc/hxrdjk part 2

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https://prnt.sc/hxreno part 1

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Severoth  Jan 8, 2018
Sort:

#1
+84253
+2

Here's a few

First one :

AC / BC  = DF  = EF

12 / 18   =  10 / EF

2 / 3   =  10   /  EF      and we can write

3/2  =  EF / 10           multiply both sides by 10

10 (3/2)  = EF  =  15

Second one :

SSS  Similarity Theorem

Third one  :

x / 42  =  6  /36

x / 42   =  1 / 6

6x  =  42

x  =  7 cm

Fourth one :

Proportional

c2

Fifth one....1st part

Corresponding Angles Postulate

2nd part

ΔACE   similar to  Δ BCD

Sixth one  :

Definition of Angle Bisector

Angle ADB  congruent to  Angle CDF

Substitution Property

Seventh One :

DB  / BA   =  CE  / AC

6  /  15  =  CE  /  25

2 / 5   =  CE  / 25     multiply through by 25

(2 / 5) (25)  =  CE   =  10

Eighth one :

CB  / CA    =  BD   / AD

7.5 / 4   =  BD   / 3        mutiply through by 3

(3/4) (7.5)   =  BD   =  x  =    5.625

CPhill  Jan 8, 2018
edited by CPhill  Jan 8, 2018
#4
+92
0

Thanks so much!

Severoth  Jan 8, 2018
#2
+84253
+2

Ninth one :

Definition of Bisector

Alternate Interior Angles Theorem

Substitution Property

Tenth one  :

[ x + 8 ]  / 10  =  [2x + 5 ] / 14      cross-multiply

14 [ x + 8 ]  =  10  [ 2x - 5 ]

14x + 112  =  20x - 50         add 50 to both sides, subtract 14x from both sides

162  =  6x              divide both sides by 6

27  =  x

Last one :

Base  =  √ [ 18^2   - 9^2 ]   =  9√ [ 2^2 - 1^2 ]  =  9√3   ≈ 15.6 in

CPhill  Jan 8, 2018
#3
+92
+1

thank  you so much!

Severoth  Jan 8, 2018

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