Let $O$ be the origin. Points $P$ and $Q$ lie in the first quadrant. The slope of line segment $\overline{OP}$ is $4,$ and the slope of line segment $\overline{OQ}$ is $5.$ If $OP = OQ,$ then compute the slope of line segment $\overline{PQ}.$
Note: The point $(x,y)$ lies in the first quadrant if both $x$ and $y$ are positive.
The slope of line PQ is
mPQ=yq−ypxq−xp=4.9029−4.85070.9806−1.2127
mPQ=−0.2249
-0.2249 is the answer.