In a certain iscoceles right triangle, the altitude to the hypotenuse has length 4. What is the area of the triangle?
Fin side length
s^2 + s^2 = 4^2
2s^2 = 16
s = sqrt 8
area = 1/ 2 Base * height
= 1/2 Sqrt8 * sqrt 8 = 4 units2
So the first thing to notice is that it is a 45 - 45 - 90 right triangle.
This means that the ratio of the sides are 1 - 1 - \(\sqrt2\)
This means that one leg has the length of\(4\over\sqrt2\) which simplifies to \(2\sqrt2\)
Now because it is a right triangle, you get \(\frac{1}{2} \times 2\sqrt2 \times 2\sqrt2\)
So the answer is 4.