+0

# Geometry

0
86
1

A right triangle has legs of length 6 and b, and a hypotenuse of length c . The perimeter of the triangle is 24 . Compute c.

Apr 17, 2022

### Best Answer

#1
+9459
+1

Since the triangle is a right triangle, by Pythagorean theorem,

$$6^2 + b^2 = c^2\\ c^2 - b^2 = 36\quad\text{---}(1)$$

Now, since the perimeter is 24,

$$6 + b + c = 24\\ b + c = 18\quad \text{---}(2)$$

From (1), we can factorize and substitute (2) into the result.

$$\begin{array}{rcl} c^2 - b^2 &=& 36\\ (c - b)(b + c) &=& 36\\ (c - b)(18) &=& 36\\ c - b &=& 2 \end{array}$$

Now, solving the system $$\begin{cases}b + c = 18\\c - b = 2\end{cases}$$ isn't too hard. We have b = 8 and c = 10.

Apr 17, 2022

### 1+0 Answers

#1
+9459
+1
Best Answer

Since the triangle is a right triangle, by Pythagorean theorem,

$$6^2 + b^2 = c^2\\ c^2 - b^2 = 36\quad\text{---}(1)$$

Now, since the perimeter is 24,

$$6 + b + c = 24\\ b + c = 18\quad \text{---}(2)$$

From (1), we can factorize and substitute (2) into the result.

$$\begin{array}{rcl} c^2 - b^2 &=& 36\\ (c - b)(b + c) &=& 36\\ (c - b)(18) &=& 36\\ c - b &=& 2 \end{array}$$

Now, solving the system $$\begin{cases}b + c = 18\\c - b = 2\end{cases}$$ isn't too hard. We have b = 8 and c = 10.

MaxWong Apr 17, 2022