In quadrilateral $ABCD$, we have $AB = BC = CD = DA$, $AC = 14$, and $BD = 48$. Find the perimeter of $ABCD$.

eileenthecoolbean
Aug 9, 2017

#1**+3 **

ANSWER: \(\boxed{100}\)

Thus if s=length of each side of the rhombus, then

\(s²=(AC/2)²+(BD/2)²\)

using Pythagoras theorem.

Calculate (Multiply S by 4 to get final answer because all four sides are equal)

\(s=√(7²+24²) =25 \)

RektTheNoob
Aug 9, 2017

#1**+3 **

Best Answer

ANSWER: \(\boxed{100}\)

Thus if s=length of each side of the rhombus, then

\(s²=(AC/2)²+(BD/2)²\)

using Pythagoras theorem.

Calculate (Multiply S by 4 to get final answer because all four sides are equal)

\(s=√(7²+24²) =25 \)

RektTheNoob
Aug 9, 2017

#2**0 **

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