The area of a trapezoid is $80$. The length of one base is $16$ units greater than the other base, and one base of the trapezoid is $12$. Find the length of the median of the trapezoid.
First, let's note that the median of the trapezoid is half the sum of the two bases.
The area is irrelevant to the problem.
If one of the bases has length \(12\), then the other base must have length \(12+16=28\)
Thus, the median is \(\frac{28+12}{2} = 40/2 = 20\)
So 20 is our ansswer.
Thanks! :)