A spherical soap bubble lands on a horizontal wet surface and forms a hemisphere of the same volume. Given the radius of the hemisphere is $3\sqrt[3]{2}$cm, find the radius of the original bubble.
volume of sphere =43∗π∗(radius of sphere)3
volume of hemisphere =12∗43∗π∗(radius of hemisphere)3
Plug in 33√2 for the radius of the hemisphere.
volume of hemisphere =12∗43∗π∗(33√2)3 =23∗π∗33∗3√23 =23∗π∗27∗2 =36π
The hemisphere has the same volume as the sphere, so....
volume of sphere = volume of hemisphere
43∗π∗(radius of sphere)3=36π
Divide both sides by pi .
43∗(radius of sphere)3=36
Multiply both sides by 3/4 .
(radius of sphere)3=27
Take the cube root of both sides.
radius of sphere=3 cm
volume of sphere =43∗π∗(radius of sphere)3
volume of hemisphere =12∗43∗π∗(radius of hemisphere)3
Plug in 33√2 for the radius of the hemisphere.
volume of hemisphere =12∗43∗π∗(33√2)3 =23∗π∗33∗3√23 =23∗π∗27∗2 =36π
The hemisphere has the same volume as the sphere, so....
volume of sphere = volume of hemisphere
43∗π∗(radius of sphere)3=36π
Divide both sides by pi .
43∗(radius of sphere)3=36
Multiply both sides by 3/4 .
(radius of sphere)3=27
Take the cube root of both sides.
radius of sphere=3 cm