+2653 In triangle ABC, the angle bisector of angle BAC meets BC at D, such that AD = AB. Line segment AD is extended to E, such that angle DBE = angle BAD = 17 degrees. Find angle ABD.
+42 Because AB=AD, triangle ABD is isosceles, so angle ABD is equal to angle ADB. We are already given angle BAD is 17 degrees. If we call the measure of angle ABD x, then 2x+17=180, so \(x=\frac{163}{2}\).
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