Let Q be the center of equilateral triangle ABC. A dilation centered at Q with scale factor -4/3 is applied to triangle ABC, to obtain triangle A'B'C'. Let S be the area of the region that is contained in both triangles ABC and A'B'C'. Find A/[ABC].
Any help would be greatly appreciated! Thanks!
I do not understand what a dilation of -4/3 is... does the triangle get smaller?
I'm pretty sure that the answer can be simplified to [A'B'C']/[ABC]. But from here I'm stuck...
+1486 Here's a similar question:
https://web2.0calc.com/questions/help_54234#r3
That's gonna look like this:
Thanks 
. However I do not understand if if there is a specific equation that should be used?
Let Q be the center of the equilateral triangle ABC. A dilation centered at Q with scale factor -4/3 is applied to triangle ABC, to obtain triangle A'B'C'. Let S be the area of the region that is contained in both triangles ABC and A'B'C'. Find S/[ABC].
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
If the side length of a triangle ABC is 3 units then the length of a side of triangle A'B'C' is 4 units.
Step 1/ Find the area of the 3 smallest triangles. Let Z be the total area of these 3 triangles.
Step 2/ Find the area of a triangle ABC.
Step 3/ Find S S = [ABC] - Z
Answer: S / [ABC] = ?
