Let Q be the center of equilateral triangle ABC. A dilation centered at Q with scale factor -4/3 is applied to triangle ABC, to obtain triangle A'B'C'. Let S be the area of the region that is contained in both triangles ABC and A'B'C'. Find A/[ABC].

Any help would be greatly appreciated! Thanks!

Guest Feb 20, 2021

#1**0 **

I do not understand what a dilation of -4/3 is... does the triangle get smaller?

Guest Feb 20, 2021

#2**0 **

I'm pretty sure that the answer can be simplified to [A'B'C']/[ABC]. But from here I'm stuck...

Guest Feb 20, 2021

#3**+1 **

Here's a similar question:

https://web2.0calc.com/questions/help_54234#r3

That's gonna look like this:

Dragan Feb 20, 2021

#6**0 **

Thanks . However I do not understand if if there is a specific equation that should be used?

Guest Feb 21, 2021

#7**0 **

Let Q be the center of the equilateral triangle ABC. A dilation centered at Q with scale factor -4/3 is applied to triangle ABC, to obtain triangle A'B'C'. Let **S** be the area of the region that is contained in both triangles ABC and A'B'C'. Find **S**/[ABC].

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If the side length of a triangle ABC is 3 units then the length of a side of triangle A'B'C' is 4 units.

Step 1/ Find the area of the 3 smallest triangles. Let **Z**** **be the total area of these 3 triangles.

Step 2/ Find the area of a triangle **ABC****.**

Step 3/ Find S **S = [ABC] - Z**

Answer: **S / [ABC] = ?**

Guest Feb 22, 2021