+448 Suppose ABCD and EFGH are congruent parallelograms with AD=10. If the area of ABCD is 112, find EN.
In parralelogram ABCD
AD=10 so BC=10
Area is equal to base*Height
Notice that EN is a height on FG, we already know FG=BC=AD=10
so 10*EN=112
EN=112/10=11.2
+2863 After rotating my head 450 degrees and looking at EFGH, I realized I could form a rectangle by moving triangle EFN with its side EF to match up to HG.
Don't worry my neck is fine
