Points $T$ and $U$ lie on a circle centered at $O$, and point $P$ is outside the circle such that $\overline{PT}$ and $\overline{PU}$ are tangent to the circle. If $\angle TOP = 45^{\circ}$, then what is the measure of minor arc $TU$, in degrees?
T
45
O P
U
TP = UP
TO = UO
PO = PO
Therefore triangle OPT is congruent to triangle OPU
Then angle TOP = angle UOP = 45
Then arc TU = angle TOP + angle UOP = 90°