Trapezoid $HGFE$ is inscribed in a circle, with $\overline{EF} \parallel \overline{GH}$. If arc $GH$ is $66$ degrees, arc $EH$ is $x^2 + 8x$ degrees, and arc $FG$ is $25 + 16x$ degrees, where $x > 0,$ find arc $EPF$, in degrees.

ABJeIIy Jun 21, 2024

#1**+1 **

Let's note something really important.

We need to find what \(\angle EPF\) is.

However, let's read through the problem. It never actually identifies what \(P\)is!

This means it's impossible to solve the problem as P is not defined.

Thanks! :)

~NTS

NotThatSmart Jun 21, 2024