+1839 Altitudes $\overline{AD}$ and $\overline{BE}$ of acute triangle $ABC$ intersect at point $H$. If $\angle AHB = 144^\circ$ and $\angle BAH = 66^\circ$, then what is $\angle HCA$ in degrees?
+1926 Before we solve the problem, let's note something important.
The sum of the angles in a triangle must add up to \(180 ^\circ\)
However, let's take a look at something.
Adding up the two angles we have, we get \(144 + 66 = 210°\)
This means that triangle AHB would have angles adding up to more than 180.
Thus, this is an invalid triangle.
Thanks! :)
~NTS
+1926 Before we solve the problem, let's note something important.
The sum of the angles in a triangle must add up to \(180 ^\circ\)
However, let's take a look at something.
Adding up the two angles we have, we get \(144 + 66 = 210°\)
This means that triangle AHB would have angles adding up to more than 180.
Thus, this is an invalid triangle.
Thanks! :)
~NTS
