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Let P_1 P_2 P_3 \dotsb P_{10} be a regular polygon inscribed in a circle with radius $1.$ Compute
P_1 P_2 + P_2 P_3 + P_3 P_4 + \dots + P_9 P_{10} + P_{10} P_1

 Jun 21, 2024

Best Answer 

 #1
avatar+1946 
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Let's note something really important first. 

P1P2+P2P3+P3P4++P9P10+P10P1 is simply the perimeter of a regular decagon. 

 

We can find one side of the decagon using the equation radius/2(1+5)

 

So the perimeter is just 10(1/2)(1+5)=5(1+5)6.18

 

So our answer is about 6.18. 

 

Thanks! :)

 

~NTS

 Jun 21, 2024
edited by NotThatSmart  Jun 21, 2024
 #1
avatar+1946 
+1
Best Answer

Let's note something really important first. 

P1P2+P2P3+P3P4++P9P10+P10P1 is simply the perimeter of a regular decagon. 

 

We can find one side of the decagon using the equation radius/2(1+5)

 

So the perimeter is just 10(1/2)(1+5)=5(1+5)6.18

 

So our answer is about 6.18. 

 

Thanks! :)

 

~NTS

NotThatSmart Jun 21, 2024
edited by NotThatSmart  Jun 21, 2024

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